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Lowering of vapour pressure due to a sol...

Lowering of vapour pressure due to a solute in `1` molal aqueous solution at `100^(@)C` is
a.`13.44 mm Hg` ,b. `14.14 mm Hg` ,c.`13.2 mm Hg` ,d. `35.2 mm Hg`

A

`13.44`mmHg

B

`14.12`mmHg

C

`31.2`mmHg

D

`35.2`mmHg

Text Solution

Verified by Experts

The correct Answer is:
A
`m=(x_(B)xx1000)/(1-x_(B)m_(A))x_(B)` =mole fraction of solute
`1=(x_(B)xx1000)/((1-x_(B))xx18)m_(A)` =mole mass of solvent
`x_(B)=0.0176`
`x_(A)=1-0.0176=0.9824`
`p=p^(@)x_(A)`
`760xx0.9824=746.62`
`Deltap=P^(@)-p=760-746.62=13.4`
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