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Relative decrease in vapour pressure of ...

Relative decrease in vapour pressure of an aqueous solution conataining `2`mol
`[Cu(NH_(3))_(3)Cl]`Cl in `3`mol `H_(2)`is `(1)/(2)`. When the given solution reation with excess fo `AgNO_(3)`solution the number moles of `AgCl`produced is

A

`1 mol AgCl`

B

`0.25 mol AgCl`

C

`2 mol AgCl`

D

`0.40 mol AgCl`

Text Solution

Verified by Experts

The correct Answer is:
A

Let degree of ionisation of the complex ,`[Cu(NH_(3))_(3)Cl]^(+)+Cl^(-)` be `alpha`
`[Cu(NH_(3))_(3)Cl[ClhArr [Cu(NH_(3))Cl]^(+)+Cl^(-)`
`i=1+alpha`
`(cancelOp)/(p_(1))=(n_(1)(1+alpha))/(n_(1)(1+alpha)+n_(2))`
`(2(1+alpha))/(1(1+alpha)+3)=(1)/(2)`
`alpha=0.5`
Total `Cl^(-)`produced `2alpha=2xx(1)/(2)=1` mole
`:. 1`mole of AgCl is produced.
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