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The latent heat of vaporisation of water...

The latent heat of vaporisation of water is `9700 "Cal/mole"` and if the b.p.is `100^(@)C`, ebullioscopic constant of water is

A

`0.513^(@)C`

B

`1.026^(@)C`

C

`10.26^(@)C`

D

`1.832^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(b)=(M_(1)RT_(0)^(2))/(100DeltaH_(v))=(18xx1.987xx(373)^(2))/(1000xx9700)=0.5313^(@)C`
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