Osmotic pressure of `30%` solution of glucose is `1.20` atm and that of `3.42%` solutin of cane sugar is `2.5` atm, The osmotic pressure of the mixture containing equal volumes of the two solutions will be

Options

A. 2.5 atm
B. 3.7 atm
C. 1.85 atm
D. 1.3 atm

Answer

C

Explanation

`pi_(f)V_(f)=pi_(1)V_(1)+pi_(2)V_(2)`
`pi_(f)=(1.2V+2.5V)/(2V)=(3.7V)/(2V)`
`pi_(f)=1.85` atm.