`1.0` molal aqueous solution of an electrolyte `X_(3)Y_(2)` is 25 % ionized. The boilling point of solution is (`K_(b)` for `H_(2)O=0.52K kg//mol`)

Options

A. `375.5K`
B. `374.04K`
C. `377.12K`
D. `373.25K`

Answer

B

Explanation

`underset(1-alpha)(x_(3)y_(2))hArr underset(n alpha)(3x^(2+))+underset(m alpha)(2y^(3-)) "for complete ionization"`
`i=1+(m+n-1)alpha`
`i=1+(2+3-1)xx0.25=1+1=2`
`DeltaT_(b)=ixxkbxxm=2xx0.52xx1=1.04`
B.P. of solution`(T_(b))=DeltaT_(b)+T_(b)^(@)=1.04+373=374.04K`