A solution of crab haemovyanin, a pigmented protein extracted from crabs,was prepared by dissolving `0.750g "in" 125cm^(3)` of aqueous medium.AT `4^(@)C` an osmotic pressure rise of `2.6`mm of the solution was observed. The solution has a density of `1.00g//cm^(3)`.Determine the molecular weight of the protein.

Options

A. `53.14xx10^(5)g//mol`
B. `52.14xx10^(5)g//mol`
C. `51.14xx10^(5)g//mol`
D. `54.14xx10^(5)g//mol`

Answer

A

Explanation

`((0.75/m))/(125)xx(8.314xx10^(5)xx10^(2))(227)=2.6xx10^(-2)(1000)`
`m=((0.75)(8.314xx10^(7))(277))/(125xx26)`
`m=53.14xx10^(5)g//mol`