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A complex of iron and cyanide ions is 10...

A complex of iron and cyanide ions is `100%`ionised ar `1`m (molal). If its elevation in b.p.is `2.08` then the complex is `(K_(b)=0.52^(@)mol^(-1)kg)`,

A

`K_(3)[Fe(CN)_(6)]`

B

`Fe(CN)_(2)`

C

`K_(4)[Fe(CN)_(6)]`

D

`Fe(CN)_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaT_(b)=ik_(b)m`
so, `i=(2.08)/(0.52xx1)=4`
so the complex is `K_(3)[Fe(CN)_(6)]`
`K_(3)[Fe(CN)_(6)]hArr 3K++[Fe(CN)_(6)]^(3-)`
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