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1.0 gof a non-electrolyte solute (molar ...

`1.0 g`of a non-electrolyte solute (molar mass`250gmol^(-1)` was dissolved in 51.2 g of benzene. If the freezing point depression constant of benzene is `5.12K kgmol^(-1)` the lowering in freezing point will be

A

`0.5K`

B

`0.4K`

C

`0.2K`

D

`0.3K`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaT=(1000xxK_(f)xxw)/(mxxW)=(1000xx5.12xx1)/(250xx51.2)=0.4K`
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1.00 g of a non-electrolyte solute (molar mass 250g mol^(–1) ) was dissolved in 51.2 g of benzene. If the freezing point depression constant K_(f) of benzene is 5.12 K kg mol^(–1) , the freezing point of benzene will be lowered by:-

1.0 g of a non-electrolyte solute( mol. Mass 250.0 g mol^(-1) ) was dissolved in 5.12 g benzene. If the freezing point depression constant, K_(f) of benzene is 5.12 K kg mol^(-1) , the freezing point of benzene will be lowered by:

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