`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:

Options

A. `0.1M`
B. `0.001M`
C. `0.01M`
D. `0.02M`

Answer

C

Explanation

Number of moles of urea=`(6.02xx10^(20))/(6.02xx10^(23))=0.001`
Molarity of solution of urea =`("number of moles of urea")/("Volume in mL")xx1000`
`=(0.001)/(100)xx1000=0.01M`