What is the molarity of `H_(2)SO_(4)` solution that has a density 1.84 g/c c at `35^(@)`C and contains 98% by weight?

Options

A. `4.18M`
B. `8.14M`
C. `18.4`
D. `18M`

Answer

C

Explanation

`98%H_(2)SO_(4)`means`100g`solution contain`98gH_(2)SO_(4)`
`(100)/(1.84)c c`contain `98gH_(2)SO_(4)`
`1000c c`solution contains
`=(98)/(100)xx1.84xx1000gH_(2)SO_(4)`
`=(98)/(100)xx(1.84xx1000)/(98) "moles of" H_(2)SO_(4)`
`=18.4M`