A `0.001` molal solution of `[Pt(NH_(3))_(4)Cl_(4)]` in water had freezing point depression of `0.0054^(@)C`. If `K_(f)` for water is `1.80`, calculating the number f `Cl^(-)` ions furnished.

Options

A. `[Pt(NH_(3))_(4)Cl_(3)]Cl`
B. `[Pt(NH_(3))_(4)Cl_(3)]Cl_(2)`
C. `[Pt(NH_(3))_(4)Cl_(3)]Cl_(3)`
D. `[Pt(NH_(3))_(4)Cl_(3)]Cl_(4)]`

Answer

B

Explanation

`DeltaT_(f)=imk_(f),0.0054=ixx1.8xx0.001`
`i=3`so it is `[Pt(NH_(3))_(4)Cl]Cl_(2)`