यदि वृत्त `x^(2)+y^(2)-3x+ky-5=0" तथा वृत्त "4x^(2)+4y^(2)-12x-y-9=0` संकेन्द्रीय हों, तो k का मान बताइए।

The circle 4x^(2)+4y^(2)-12x-12y+9=0

The circle 4x^(2)+4y^(2)-12x-12y+9=0

If circles x^(2) + y^(2) - 3x + ky - 5 = 0 " and " 4x^(2) + 4y^(2) - 12x- y - 9 = 0 are concentric , then k =

If the two circle x^(2) + y^(2) - 3x + ky - 5 = 0 and 4x^(2) + 4y^(2) - 12x - y - 9 = 0 are concentric , then : k =

The value of k for which the circles x^2 + y^2 - 3x + ky - 5 = 0 and 4x^2 + 4y^2 - 12x - y - 9 = 0 become concentric is:

If 2x^(2)+2y^(2) +4x+5y+1=0 and 3x^(2)+3y^(2)+6x -7y+3k=0 are orthogonal ,then value of k is