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[" 123."56-:(1)/(3)(15+12-(9+6-5+7))=?],...

[" 123."56-:(1)/(3)(15+12-(9+6-5+7))=?],[[" (A) "8," (B) "9," (C) "7," (D) "12]]

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56/(1/3 {15+12-(9+6-bar(5+7))})=

3, 7, 6, 5, 9, 3, 12, 1, 15, (......) (a) 18 (b) 13 (c) -1 (d) 3

1, 5, 5, 9, 7, 11, 11, 15, 12, 17

The average of 4(3/5) , 2(2/3) , 6(8/9) , 7(7/15) , 3(5/9) is:

(3) / (6) + (3.5) / (6.9) + (3.5.7) / (6.9 * 12) + ..... prop =

The value of: [(5/7 " of " 1 (3)/(8) " of " 6/7)] div [1-(1)/(7) xx ( 5/12 +(1)/(3)) ] xx ((1)/(7) -(1)/(9))/((1)/(7) +(1)/(9))