Home
Class 11
PHYSICS
A body of mass 5 kg is moving with veloc...

A body of mass 5 kg is moving with velocity of `v=(2hati+6hatj)ms^(-1)` at t=0s. After time t=2s, velocity of body is `(10 hati+6 hatj)`, then change in momentum to body is

Promotional Banner

Similar Questions

Explore conceptually related problems

A cricket ball of mass 150 g has an intial velocity u = (3 hati + 4 hatj)ms^(-1) and a final velocity v = -(3hati + 4 hatj) ms^(-1) , after being hit. The change in momentum (final momentum - initial momentum ) is (in Kg ms^(1) )

A cricket ball of mass 150 g has an intial velocity u = (3 hati + 4 hatj)ms^(-1) and a final velocity v = -(3hati + 4 hatj) ms^(-1) , after being hit. The change in momentum (final momentum - initial momentum ) is (in Kg ms^(1) )

A cricket ball of mass 150 g has an intial velocity u = (3 hati + 4 hatj)ms^(-1) and a final velocity v = -(3hati + 4 hatj) ms^(-1) , after being hit. The change in momentum (final momentum - initial momentum ) is (in Kg ms^(1) )

A cricket ball of mass 150 g has an initial velocity bar(u)=(3hati-4hatj)ms^(-1) and a final velocity bar(v)=-(3hati-4hatj)ms^(-1) after being hit. The change in momentum (final momentum -initial momentum) is ("in kg ms"^(-1))

A cricket ball of mass 150 g has an initial velocity bar(u)=(3hati-4hatj)ms^(-1) and a final velocity bar(v)=-(3hati-4hatj)ms^(-1) after being hit. The change in momentum (final momentum -initial momentum) is ("in kg ms"^(-1))

A body is projected with a velocity vecv =(3hati +4hatj) ms^(-1) The maximum height attained by the body is: (g=10 ms^(-2))

A body is projected with a velocity vecv =(3hati +4hatj) ms^(-1) The maximum height attained by the body is: (g=10 ms^(-2))