Home
Class 12
CHEMISTRY
An element crystallises in fee lattice h...

An element crystallises in fee lattice having edge length `350` Maximum raduis of the atoms which can be placed in the internal site without distoring the structure is

A

`58.55` pm

B

117 pm

C

`51.23` pm

D

83 pm

Text Solution

Verified by Experts

The correct Answer is:
c

For fcc stracture
`((r_(+))/(r_(-))) = 0.414` for octahedral void
`= 0.225` for tetrabeederal void
Thus maximum packing can be octabodral void
`r_(+) = 0.414 r`
Also `r_(-) = (a)/(2sqrt(2)`
`:. r_(+) = 0.414 (a)/(2sqrt(2)) = 0.414xx(350)/(2sqrt(2)) = (144.9)/(2sqrt(2)) = 51.23` pm
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    A2Z|Exercise Ccp, Hcp, Octahedral And Tetral Voids|17 Videos
  • SOLID STATE

    A2Z|Exercise Structure, Coordination Number, Radious Ratio Rule, Density Of Unit Cell|72 Videos
  • SOLID STATE

    A2Z|Exercise Section D - Chapter End Test|30 Videos
  • P BLOCK ELEMENTS ( GROUP 15,16,17,18)

    A2Z|Exercise Section D - Chapter End Test|30 Videos
  • SOLUTIONS

    A2Z|Exercise Section D - Chapter End Test|30 Videos

Similar Questions

Explore conceptually related problems

An element crystallises in f.c.c. lattice having edge length 400 p m . Calculate the maximum diameter, which can be placed in interstitial sites without disturbing the structure.

A metal crystallizes in fcc arrangement with edge length equal to 400 nm. Calculate maximum possible radius of the atom which can fit in the voids without disturbing the crystal structure?

In face - centred cubic (fcc) crystal lattice, edge length is 400 pm. Find the diameter of the greatest sphere which can be fitted into the interstital void without distortion of the lattice.

A metal crystallises in b.c.c. lattice. The per cent fraction of edge length not covered by atom is :

What would be the edge length of that fcc unit cell in which an atom with maximum diameter 117.1 pm can be placed in between its interstitial sites without changing its structure ?

A2Z-SOLID STATE-Ssc, Fcc, Bcc, Nearest Neighbouring Distance, Next-Nearest Neighbouring Distance, Packing Fraction
  1. In a solid AB having the NaCl structure, A atom occupies the corners o...

    Text Solution

    |

  2. A swubstance A(x)B(y) crystallises in a face cubic centred cubic (fcc)...

    Text Solution

    |

  3. An element crystallises in fee lattice having edge length 350 Maximum ...

    Text Solution

    |

  4. The number of atoms present in unit cell of a monoatomic substance of ...

    Text Solution

    |

  5. Sodium metal crystallises in body centred cubic lattic with cell edge ...

    Text Solution

    |

  6. The volume of atom present in a face-centred cubic unit cell of a meta...

    Text Solution

    |

  7. The edge of unit of FC C Xe crystal is 620 pm .The radius of Xe atom i...

    Text Solution

    |

  8. A compound is formed by element A and B .This crystallizes in the cubi...

    Text Solution

    |

  9. An ionic compound has a unit cell consisting of A ions at the corners ...

    Text Solution

    |

  10. Copper crystallises in fcc with a cell length of 361 pm .What is the r...

    Text Solution

    |

  11. Percentage of free space in cubic close packed structure and in body c...

    Text Solution

    |

  12. Percentage of free space in cubic close packed struchure and in body c...

    Text Solution

    |

  13. In face centred cubic unit cell edge length is

    Text Solution

    |

  14. The edge length of a face centred cubic cell of an ionic substance is ...

    Text Solution

    |

  15. An elementoccurring in the bcc structure has 12.08 xx 10^(23) unit cel...

    Text Solution

    |

  16. The interionic distance for cesium chloride crystal will be

    Text Solution

    |

  17. Sodium metal crystallises in body centred cubic lattic with cell edge ...

    Text Solution

    |

  18. Lithium forms body centred cube structure .The length of the side of i...

    Text Solution

    |

  19. In a face centerd lattice of X and YX atoms are present at the corners...

    Text Solution

    |

  20. The fraction of total volume occupied by atoms in a simple cube is

    Text Solution

    |