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The fraction of total volume occupied by...

The fraction of total volume occupied by atoms in a simple cube is

A

`(pi)/(2)`

B

`sqrt(3pi)/(8)`

C

`sqrt(2pi)/(6)`

D

`(pi)/(6)`

Text Solution

Verified by Experts

The correct Answer is:
D

In a simple cube arrangement , the number of atoms is `1`
Also `a = 2r`
Therefore packing fraction
`= ("volume occupied by one atom")/("volume of unit cell")`
`(4//3m^(3))/(a^(3)) = (4//3 pi r^(3))/((2r)^(2)) = (pi)/(6)`
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