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A given metal crystallises out with a cu...

A given metal crystallises out with a cubic structure having edge length of `361 "pm"` .If there are metal atoms in one cell, what is the radius of one atoms?

A

`80` pm

B

`108` pm

C

`40` pm

D

`127` pm

Text Solution

Verified by Experts

The correct Answer is:
d
`Z = 4,i.e.` structure is fcc
Hence
`r = (a)/(2sqrt(2)) = (361)/(2sqrt(2))`
` = 127.65 "pm" = 127` pm
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