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The ionic radii of A^(+) and B^(-) ions ...

The ionic radii of `A^(+) and B^(-)` ions are `0.98 xx 10^(-10) and 1.81 xx 10^(-10) m` .The coordinatyion number of each ion in `AB` is

A

`2`

B

`6`

C

`4`

D

`8`

Text Solution

Verified by Experts

The correct Answer is:
b
`(r_(A+))/(r_(B+)) = (0.98 xx 10^(-10))/( 1.81 xx 10^(-10)) = 0.54`
`as (r^(+))/(r^(-)) `is in rabge `414 - 732` so octabedral
Co-ordination no of each in `6` like `NaCI` structure
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