An element (atomic mass `= 100 g//mol`) having bcc structure has unit cell edge 400 pm .Them density of the element is

Options

A. `10376 g//cm^(3)`
B. `5.188g//cm^(3)`
C. `7.289 g//cm^(3)`
D. `2.144g//cm^(3)`

Answer

b

Explanation

`r = (n xx M)/(a^(3) xx N_(0) xx 10^(-30))`
`= (2 xx 100)/((400)^(3) xx (6.02 xx 10^(23)) xx 10^(-30)) = 5.188 g//cm^(3)`