An ionic compound `AB` has `ZnS` type of structure if the radius `A^(+)` is `22.5` pm , then the ideal radius of `B` is

Options

A. `54.35` pm
B. 100 pm
C. `145.16` pm
D. None

Answer

B

Explanation

Since ions compound `AB` has `ZnS` type of structure therefore it has tetrahedral holes, for which
`("radius of cation")/("radius of anion") = 0.225`
`(r_(+))/(r_(-)) = 0.225`
`(22.5)/(r_(-)) = 0.225`
Hence `r_(-) = 100` pm