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In A^(+)B^(-) ionic compound radii of A^...

In `A^(+)B^(-)` ionic compound radii of `A^(=) and B^(-)` ions are `180 "pm "` and `187` pm respectively .The crystal structure of this compound will be

A

`NaCl` type

B

`CaCl` type

C

`ZnS` type

D

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The correct Answer is:
B

`r_(+) // r_(-) = (180)/(187) = 0.962 `which lies in the range of `0.732 - 1.000` hence coordination number `= 8 `i.e. the structure is `CaCI` type
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