The equivalent conductance of `Ba^(2+)` and `Cl^(c-)` are `63.5ohm^(-1) cm^(2) eq^(-1)` and `76 ohm^(-1) cm^(2)eq^(-1)`, respectively, at infinite dilution . The equivalent conductance `(` in `oh^(-1) cm^(2))` of `BaCl_(2)` at infinite dilution will be

Options

A. ` 101 .5`
B. `203.5 cm^(-1)`
C. `139.5 dm^(-1)`
D. `1.62 m^(-1)`

Answer

C

Explanation

` lambda^("infty") BaCI_2= 1/2 labmda ^("infty")Ba^(2+) + lambdaCI^(-)`
` =(127)/2 + 76 = 139.5 "ohm"^(-1) cm^(-1) eq^(-1)`.