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The limiting molar conductivities Lambda...

The limiting molar conductivities `Lambda^@` for `NaCL, KBr` and `KCI` are ` 126, 152` and `150 S cm^2 ,ol^(-1)` respectively . The `Lambda^@` fro `NaBr S cm^@ "mol"^(-1)` is :

A

`302`

B

`176`

C

`278`

D

`128`

Text Solution

Verified by Experts

The correct Answer is:
D
` Lambda_(NaBr)^@ =Lambda_(NaCI)^@ + Lambda_(KBr)^@-Lambda_(NaCI)^@`
` =126+ 152 - 150 = 128 S cm^2 mol^(-1)`.
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A2Z-ELECTROCHEMISTRY-Section D - Chapter End Test
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