For `H^(+) ` the value of `lambda^(infty)=349.8 S cm^2 eq^(-1)`. Calculate the mobilities of `H^(+)` ion and its velocity is it is in a cell in which the electrodes are `5 cm` apart and to which a potential of `2` volts is applied .

Options

A. `3.575 xx 10^(-3) cm^2 "volt"^(-1) sec^(-1), . 43 xx 10^(-3) cm sec^(-1)`
B. ` 5.2 xx 10^(-4) cm^2 "volt"^(-1) sec^(-1) , 2. 08 xx 10^(-4) cm sec^(-1)`
C. `3.2 xx 10^(-4) cm^2 "voly"^(-1) sec^(-1), 1.05 xx 10^(-3) cm sec^(-1)`
D. None of these

Answer

A

Explanation

Velocity `= 1/(2 xx 349.8) = 1.43 xx 10^(-3) cm//sec`
Mobility ` =1,42 xx 10^(-3) xx 5/2 = 3.575 xx 10^(-3)`.