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The equivalent conductance of an infinit...

The equivalent conductance of an infinitely dilute solution of `NH_4CI` is `150` and the ionic conductance of `OH^(-)` and `CI^(-)` ions are `198` and ` 76` respectively. If the equivalent conductance of a ` 0.01 N` solution of ` NH_4 OH` is `9.6` Wat will be its degree of dissociation ?

A

` 0.0 3431`

B

`0.0103`

C

`0.96`

D

`0.414`

Text Solution

Verified by Experts

The correct Answer is:
A
`Lambda_(NH_4OH)^@ =150 - 76 + 198 = 272`
`alpha = (9.6)/( 272) = 0.0353`.
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The equivalent conductances of an infinitely dilute solution NH_(4)CI is 150 and the ionic conductances of OH^(-) and CI^(-) ions are 198 and 76 respectively. What will be the equivalent conductance of the solution of NH_(4)OH at infinite dilution. if the equivalent conductance of a 0.01N solution NH_(4)OH is 9.6, what will be its degree of dissociation.

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A2Z-ELECTROCHEMISTRY-Section D - Chapter End Test
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