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At 25^@ C specific conductivity of a nor...

At` 25^@ C` specific conductivity of a normal solution of ` KCI` is ` 0. 0022765` ohm. The resistance of cell is `400` ohms. The cell constant is .

A

` 0. 815`

B

` 1.106`

C

` 1.016`

D

` 2.016`

Text Solution

Verified by Experts

The correct Answer is:
B
Cell constant = `("Specific conductivity")/("Observed conductance" ) = (0.002765)/(1/R)`
` = 0.002765 xx400 = 1.106`.
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