The specific conducitvity of a saturated solution of `AgCI` is ` 3.40 xx 10^6 "ohm"^(-1) cm^(-1) ` at ` 25^@C`. If ` lambda_(Ag+) = 62.3 "ohm"^(-1) cm^2 "mol"^(-1)` and `lambda_(CI-) = 67.7 "ohm"^(-1) cm^2 "mol"^(-1)`, the solubility of `AgCI` at `25^@C` is.

Options

A. ` 2.6 xx 10^(-5) "mol" L-1`
B. ` 3.731 xx 10^(-3) "mol" L-1`
C. ` 3.731 xx10^(-5) "mol" L-1`
D. ` 2.6 xx 10^(-3) g L-1`

Answer

A

Explanation

`lambda_(sec) = 62.3 + 67.7 = 130 "ohm"^(-1) cm^2 "mol"^(-1)`
` S= ( 3.4 xx 10^(-6))/(130) "mol"//cm^3 = 2.6 xx 10^(-5) "mol"//L`.