Amount of electricty that can depostit `108 g` of silver from `AgNO_3` aikyruib ua

Options

A. `1` ampere
B. ` 1` freaday
C. `1` coulomb
D. None of the above

Answer

B

Explanation

` Ag^(+) + e^(-) rarr Ag, E_(Ag) = ("Atomic Mass")/1 = 108`
Number of faraday `=(W_(Ag))/(E_(Ag)) = ( 108)/(108) = 1`
`Al^(3+) + 3 e^(-) + rarr Al`
`E_(AI) = (27)/3 =9`
`W_(AI) = E_(AI) xx` No.of faradays `=9 = 4 45 g`.