On passing `0.1 F` of electricity through aluminimum chloride, the amount of aluminimu metal deposited on cathode is `(A1 =27)` .

Options

A. ` 0.27 g`
B. ` 0.3 g`
C. ` 0.9 g`
D. ` 2.7 g`

Answer

C

Explanation

At cathode , `At^(3+) + 3e^(-) rarr AI`
`E_(Al) = (27)(3) =9`
` W_(Al) = E_(Al) xx ` No. of faradays ` =9 xx 0.1 =0.9 g`.