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To deposit 0.6354 g of copper by electro...

To deposit `0.6354 g` of copper by electrolysis of aqueous cupric sulpbate solution, the amount of electricity required (in coulmmbs) is.

A

` 1930`

B

` 4825`

C

` 3860`

D

` 9650`

Text Solution

Verified by Experts

The correct Answer is:
A
`Cu^(++) + 2e^(-_ rarr Cu`
`E_(Cu) = (63.54)/2 = 31 .77`
Amount of electricity requird to depostit ` 0.6354` gm of `Cu`
` = ( 96500 xx 0.6354)/(31.77) = 1930 C`.
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