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During electrolysis of an aqeous solutio...

During electrolysis of an aqeous solution of sodium sulphate if 2.4 Lof oxygen at STP was liberated at anode. The volume of hydrogen at STP, liberated at cathode would be:

A

` 1.2 L`

B

` 2.4 L`

C

` 2.6 L`

D

` 4 .8 L`

Text Solution

Verified by Experts

The correct Answer is:
D
AT cathode , At anode
`As^+ +e rarr NaH_2 rarr2H^+ +2e^-`
So 1 mole has ` 2.4`
So `2` mole has ` =2.4 xx 2 = 4.8`.
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