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Civen E^@ for Cu^(2+) rarr Cu^+ is + ...

Civen `E^@` for ` Cu^(2+) rarr Cu^+ ` is ` + 0.15 V` and ` Cu^+ rarr Cu ` is ` +0.05 V`
Calculate ` E^@` for ` Cu^(2+) rarr Cu`.

A

` + 0.325 V`

B

` + 0.125 V`

C

` + 0.250 V`

D

` + 0. 160 V`

Text Solution

Verified by Experts

The correct Answer is:
A
` Cu^2 +le^- rarr Cu^+ E_1 =0.15 `…(i)
`Cu +le^- rarr Cu E_2 =0.50` …(ii)
`Cu^2 +le^- rarr Cu E_3 =?` …(iii)
Clearly (iii) = (i) + (ii)
` -DeltaG_3^0 + (-Delta G_2^0)`
` 2xx Fxx E_3 = 1 xx F E_1 +1 xx Fxx E_2`
`E_3 = (0.65)/2 =0.324 V`.
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The E^(@) values for the changes given below are measured againest NHE at 27^(@)C . Cu^(2+) + e rarr Cu^(+), E^(@) = + 0.15 V , Cu^(+) + e rarr Cu, E^(@) = + 0.50 V , Zn^(2+) + 2e rarr Zn, E^(@) = - 0.76 V The temperature coefficient of emf a cell designed as Zn"|"underset(1 M)(Zn^(2+))"||"underset(0.1 M)(Cu^(2+))"|"Cu is -1.4 xx 10^(-4)V per degree. For a cell reaction in equilibrium DeltaG = 0 and DeltaG^(@) = -2.303 RTlog_(10)K_(c) . The heat of reaction and entropy change during the reaction are are related by DeltaG = DeltaH - TDeltaS . The E^(@) for the reaction : 2Cu^(+) rarr Cu^(2+) + Cu is:

The E^(@) values for the changes given below are measured againest NHE at 27^(@)C . Cu^(2+) + e rarr Cu^(+), E^(@) = + 0.15 V , Cu^(+) + e rarr Cu, E^(@) = + 0.50 V , Zn^(2+) + 2e rarr Zn, E^(@) = - 0.76 V The temperature coefficient of emf a cell designed as Zn"|"underset(1 M)(Zn^(2+))"||"underset(0.1 M)(Cu^(2+))"|"Cu is -1.4 xx 10^(-4)V per degree. For a cell reaction in equilibrium DeltaG = 0 and DeltaG^(@) = -2.303 RTlog_(10)K_(c) . The heat of reaction and entropy change during the reaction are are related by DeltaG = DeltaH - TDeltaS . The E^(@) for Cu rarr Cu^(2+) + 2e is :

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The E^(@) values for the changes given below are measured againest NHE at 27^(@)C . Cu^(2+) + e rarr Cu^(+), E^(@) = + 0.15 V , Cu^(+) + e rarr Cu, E^(@) = + 0.50 V , Zn^(2+) + 2e rarr Zn, E^(@) = - 0.76 V The temperature coefficient of emf a cell designed as Zn"|"underset(1 M)(Zn^(2+))"||"underset(0.1 M)(Cu^(2+))"|"Cu is -1.4 xx 10^(-4)V per degree. For a cell reaction in equilibrium DeltaG = 0 and DeltaG^(@) = -2.303 RTlog_(10)K_(c) . The heat of reaction and entropy change during the reaction are are related by DeltaG = DeltaH - TDeltaS . The heat of reaction for the change Zn+underset(0.1 M)(Cu^(2+)) hArr underset(1M)(Zn^(2+))+Cu at 27^(@)C is :

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