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Give, E(Cr^(3+)//Cr)^o =- 0. 74 V, E(CnO...

Give, `E_(Cr^(3+)//Cr)^o =- 0. 74 V, E_(CnO_2^-)^o = 1.36 V,`
Based on the data given above, strongest oxidizing agent will be .

A

`Cl`

B

`Cr^(3+)`

C

`Mn^(2+)`

D

`MnO_4^-`

Text Solution

Verified by Experts

The correct Answer is:
D
Higher the SRP (Standard Reduction Potential) stronger is the oxidizing agent. Among the given electrode potentials,
`E_(MnO_(4)^(-)//Mn^(2+))` is highest.
Hence, ` MnO_4^-` is the strongest oxidizing agent .
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