The standard EMF of a Daniell cell is `1.10 ` volt. The maximum electrical work obtained from the Daniell cell is .

Options

A. `212.3 KJ`
B. `175.4 KJ`
C. ` 106.15 KJ`
D. ` 53.07 KJ`

Explanation

To find the maximum electrical work obtained from a Daniell cell with a standard EMF of 1.10 volts, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values:**
- Standard EMF (E) = 1.10 volts
- Number of electrons transferred (n) in the Daniell cell reaction = 2 (from the balanced reaction: Zn + Cu²⁺ → Zn²⁺ + Cu)

2. **Use the Formula for Maximum Work:**
The maximum electrical work (W) done by the cell can be calculated using the formula:
\[ W = -\Delta G^\circ = n \cdot F \cdot E \]
where:
- \( \Delta G^\circ \) is the change in Gibbs free energy,
- \( n \) is the number of moles of electrons transferred,
- \( F \) is Faraday's constant (approximately 96500 C/mol),
- \( E \) is the standard EMF of the cell.

3. **Substitute the Values:**
Plugging in the values we have:
\[ W = n \cdot F \cdot E = 2 \cdot 96500 \, \text{C/mol} \cdot 1.10 \, \text{V} \]

4. **Calculate the Work Done:**
\[ W = 2 \cdot 96500 \cdot 1.10 = 212300 \, \text{J} \]
To convert this to kilojoules:
\[ W = \frac{212300}{1000} = 212.3 \, \text{kJ} \]

5. **Final Answer:**
The maximum electrical work obtained from the Daniell cell is **212.3 kJ**.