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The reduction potential of a half-cell c...

The reduction potential of a half-cell consisting of a Pt electrode immersed in `1.5 M Fe^(2+)` and ` 0.015 M Fe^(3+)` solutin at `25^@ C` is `(E_(Fe^(3+)//Fe^(2+))^@ = 0.770 V)` is .

A

` 0. 652 V`

B

` 0.88 V`

C

` 0. 710 V`

D

` 0.850 V`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_("cell") = 0.77 - ( 0.059) /1 log. ( 1.5)/( 0.015) = 0. 652 V`.
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