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The cell , Zn | Zn^(2+) (1M) || Cu^(2+) ...

The cell , `Zn | Zn^(2+) (1M) || Cu^(2+) (1M) Cu (E_("cell")^@ = 1. 10 V)`,
Was allowed to be completely discharfed at `298 K `. The relative concentration of `2+` to `Cu^(2+) [(Zn^(2=))/(Cu^(2+))]` is :

A

abtukig` (24.08) `

B

` 37 .3`

C

` 10^(37.3)`

D

` 9.65 xx 10^4`

Text Solution

Verified by Experts

The correct Answer is:
C
`E_("cell") =E_("cell")^@ - (0.591)/n log Q`
Where, ` Q = ([Zn^(2+)])/([Cu^(2+)])`
For complete discharde `E_("cell") =0`
So `E_("cell")^@ = ( 0.591)/2 log. ([Zn^(2+)])/([Cu^(2+)])`
`:. ([Zn^(2+)])/([Cu^(2+)])` =10^(37.3)`.
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