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The EMF of the following cell : Cd(s)|...

The `EMF` of the following cell `:`
`Cd(s)|CdCl_(2)(0.10M)|AgCl(s)|Ag(s)` is `0.6915V` at `0^(@)C` and `0.6753V` at `25^(@)C` . The `DeltaH` of reaction in `kJ` at `25^(@)C` is

A

` - 17 k J`

B

` -234 . 7 k J`

C

` + 123 . 5`

D

` - 167 . 26 k J`

Text Solution

Verified by Experts

The correct Answer is:
D

`Delta H=- nFE + nFT (delE)/(delT)_p`
` =- 2 xx 96500 xx 0. 6753 + 2 xx 96500 xx 298`
` =((0.67553 -0.915)/(25)) =- 167.6 k J`
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