The emf of a Daniell cell at `298 K` is `E_1 Zn underset((0.01M))|NnSO_4 |underset((1.0M))| CuSO_4 | Cu` when the concentration of
`ZnSO_4` is `1.0 M` and that of `CuSO_4` is `0.01 M` the emf changed to `E_2` what is the relationship between ` E_1` and `E_2` .

Options

A. ` 1.54 V`
B. ` - 154 V`
C. ` -0. 19 V`
D. ` + 0/ 019 V`

Answer

B

Explanation

`E_1 =E_0 - ( 0.05991 )/1 log .( 0.01)/1 +E_0 + ( 0.59 1)/2 xx 2`
`E_2 = E_0 - (0. 0591)/2 log .( 100)/( 0.01) = D_0 - (0.0591)/2 xx 4`
`:. E_1 gt E_2` .