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The statdard electrode potential of the ...

The statdard electrode potential of the half cells is given below:
`Zn^(2+) +2e^- rarr Nn, E=- 7. 62 V`,
` Zn^(2+) +2e^- rarr Nn, E=- 7. 81 V`,
The emf of the cell `Fe^(2+) + Zn rarr Zn^(2+) + De` is ,

A

` 1.54 V`

B

` -1. 54 V`

C

` -0 / 19 V`

D

` + 0. 19 V`

Text Solution

Verified by Experts

The correct Answer is:
C
.
`EMF =E_("cathode ") - E_("anode ") =- 7.81 - (- 7. 62)`
`EML =- 0 19 V`.
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