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The equilbrium constant for the reaction...

The equilbrium constant for the reaction : `Cu + 2 Ag^(+) (aq) rarr Cu(2+) (aq) +2 Ag, E^@ = 0. 46 V` at ` 299 K` is

A

` 2.0 xx 10^(10)`

B

` 3.9 xx 10^(15)`

C

` 0.330 V`

D

` 1.212 V`

Text Solution

Verified by Experts

The correct Answer is:
B
` E^@ = (0.059)/2 log K_C`
`0.46 = ( 0.059)/2 log K_C`
`log K_C = 15 . 59`
`:. K _C = 3.9 xx 10^(15)` .
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