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The correct value of emf of cell is give...

The correct value of emf of cell is given by
(i) `E_("cell") = E_(OP)` andode `- E _(RP)` cathode (ii) (i) `E_("cell") = E_(RP)` andode - E _(RP)` cathode (iii) (i) `E_("cell") = E_(OP)` andode `- E _(RP)` cathode .

A

(iii) and (i)

B

(i) and (ii)

C

(iii) and (iv)

D

(ii) and (iv)

Text Solution

Verified by Experts

The correct Answer is:
D
`E_(Opanode) + E_(RPCathode ) = E_(Opanode) - E_(Opcathode)`.
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