The electrode pptenticals for
` Cu^(2+) (aq) +e^(-) rarr Cu^+ (aq) `
and ` Cu^+ (aq) + e^- rarr Cu (s)`
are `+ 0.15 V` and ` +0. 50 V` repectively. The value of `E_(cu^(2+)//Cu)^@` will be.

Options

A. ` 0.150 V`
B. ` 0.325 V`
C. ` 0. 500 V`
D. ` 0. 650 V`

Answer

B

Explanation

` Cu_(aq)^(2+) + 2e rarr Cu_(aq)^(+) , Delta G_(1)^(@) =- 9 1 xx 0. 15 xx F]`
` Cu_(aq)^+ +e rarr Cu , Delta G_2^@ =- [1 xx 0. 50 xx F]`
On adding
`:. Cu_(aq)^(2+) = 2e rarr Cu, Delta G_3^@ =- [2 xx E_3^@ xx F]`
`:. 2 E_3^@ = 0.56 V` or `E_3^2 = 0. 325 V`