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Electode potential of Zn^(2+) //Zn is ...

Electode potential of ` Zn^(2+) //Zn` is ` -0 . 7 V` and that of `Cu^(2+) //Cu si = 0. 3 4 V`. The EMF of the cell consttructed between these two elctrodes is .

A

` 1.10V`

B

` 0.42 V`

C

` -1.1V`

D

` -0. 42 V`

Text Solution

Verified by Experts

The correct Answer is:
A
` E_(cell)^@ -D_("cathode")^@ -D_("anode")^@`
` =0. 34 - (-0. 76) =1.10 V`.
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