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Given standard electode potenitals Fe...

Given standard electode potenitals
` Fe^(2+) + 2e^(-) rarr Fe, E^@ =- 0. 44 V ` ………………(1)
` Fe^(3+) + 2e^(-) rarr Fe, E^@ =- 0. 036 V` ………….(2)
The standard electrode pptential `E^@ ` for
`Fe^(2+) + e rarr Fe^(2+)` is.

A

`-0.476 V`

B

` -0.404 V`

C

` +0.404 V`

D

` +0.772 V`

Text Solution

Verified by Experts

The correct Answer is:
D
`Delta G^@ =- nE^@ F `
` Fe^(2+) + 2e^(-) rarr Fe`
` DeltaG^@ =- 2 xx Fxx (-0.440 V) =0.880 F` …(i)
` Fe^(3+) + 3e^- rarr Fe`
`DeltaG^@ =- 3 xx F (-0 . 036 ) = 0. 108 F` …(ii)
On subtracting equation (i) form (ii)
`Fe^(3+) + e^- rarr Fe^(2+)`
`DeltaG^@ =0. 108 F- 0.880 F=- 772 F`
`E^@` for the reaction
`=- (Delta G^@)/(nF) =- ((-0.772F))/(1xx F) = + 0. 772V`.
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