The standard emf of a cell having one electron change is found to be `0.591 V` at `25^@ C`, The equilibrium constant of the reaction is :

Options

A. ` 1^(-10)`
B. `29.5 xx 10^(-2)`
C. ` 10`
D. `1xx10^(1)`

Answer

D

Explanation

`DeltaG =- nFE^@`
` DeltaG =- 2. 303 RT log K, nFE^@ = 2.303 RT log K`
`log K = (nFE^@)/( 2.303RT) = (2 xx96 500 xx 0. 295)/( 2.303xx 8341 xx 198)`
`log K= 9.97 = K= 1 xx 10^(10)`.