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Given l//a=0.5 cm^(-1), R= 50 "ohm", N= ...

Given `l//a=0.5 cm^(-1), R= 50 "ohm", N= 1.0.` The equivalent conductance of the electrolytic cell is .

A

` 10 "ohm"^(-1) cm^2 mol^(-1)`

B

` 20 "ohm"^(-1) cm^2 mol^(-1)`

C

` 300 "ohm"^(-1) cm^2 mol^(-1)`

D

` 100 "ohm"^(-1) cm^2 mol^(-1) `

Text Solution

Verified by Experts

The correct Answer is:
A
` l//a =0.5 cm^(-1) , R =50 `ohm
`p= (RA)/ = (50)/(0.5) = 100`
`Lambda= k xx (100)/N = 1/p xx (100)/N`
` = 1/(100) xx (100) /1 `
`= 10 "ohm"^(-1) cm^2 gm eq^(-1)`,
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