The standard emf of a cell having one electron change is found to be `0.591 V` at `25^@ C`, The equilibrium constant of the reaction is :

Options

A. `1 xx 10^(-10)`
B. `29. 5 xx 10^(-2)`
C. `10`
D. `1xx 10^(10)`

Answer

d

Explanation

` DeltaG =- nFE^@`
` DeltaG =- 2. 303 RT log K,nFE^2 = 2.303 RT log K`
` log K = (nFE^2)/( 2.303RT) = (2 xx96 500 xx 0. 295)/( 2.303xx 8341 xx 198)`
`log K= 9.97 = K= 1 xx 10^(10)`.