The resistance of `0. 01 N NaCl` solution at `25^@C` is `200 Omega` . Cell constant of conductivity cell is ` 1 cm^(-1)` . The equivalent conductance is .

Options

A. ` 5 xx10^2 Omega cm^2 eq^(-1)`
B. ` 6 xx 10^3 Omega cm^2 eq^(-1)`
C. ` 7 xx 10^4 Omega cm^2 eq^(-1)`
D. ` 8 xx 10^5 Omega cm^2 eq^(-1)`

Answer

A

Explanation

` lambda=k xx V 1/R xx 1/a xx V = 1/( 200) xx 1 xx 10.000`
` =5 xx 10^2 Omega^(-1) cm^2 eq^(-1)`.