For a reaction `(1)/(2)A rarr 2B`, rate of disappearance of `'A'` is related to the rate of apperance of `'B'` by the expression:

Options

A. `-(d[A])/(d t) = (1)/(2)(d[B])/(d t)`
B. `-(d[A])/(d t) = (1)/4(d[B])/(d t)`
C. `-(d[A])/(d t) = (d[B])/(d t)`
D. `-(d[A])/(d t) = 4(d[B])/(d t)`

Answer

B

Explanation

`(1)/(2)A rarr 2B`
`(-2d[A])/(d t) = + (d[B])/(2d t)`
`-(d[A])/(d t) = (1)/(4) (d[B])/(d t)`