For the reaction `H_(2)(g)+I_(2)(g) hArr 2HI(g)`, the rate of reaction is expressed as

Options

A. `-(Delta[I_(2)])/(Delta t) = - (Delta[H_(2)])/(Delta t) = (1)/(2)(Delta[HI])/(Delta t)`
B. `(Delta[I_(2)])/(Delta t) = - (Delta[H_(2)])/(Delta t) = (Delta[HI])/(2Delta t)`
C. `(Delta[H_(2)])/(Delta t) = (1)/(2) (Delta[I_(2)])/(Delta t) = -(Delta[HI])/(Delta t)`
D. None of these

Answer

A

Explanation

For given reaction:
`-(Delta[I_(2)])/(Delta t) = -(Delta[H_(2)])/(Delta t) = (1)/(2) (Delta[HI])/(Delta t)`